已知cos=五分之三,cos

原式=2sin(π/5)cos(π/5)cos(2π/5)/[2sin(π/5)]=sin(2π/5)cos(2π/5)/[2sin(π/5)]=2sin(2π/5)cos(2π/5)/[4sin(π

锐角sinα>0sin²α+cos²α=1sinα=4/50

cos53.13=3/5

sin二分之π,cos二分之π,tan二分之π不是等于1,0,∅

sin二分之A-cos二分之A=五分之一,(sinA/2-cosA/2)^2=1/25,(sinA/2)^2+(cosA/2)^2-2sinA/2cosA/2=1/25,1-sinA=1/25,sin

∵cos（x-π/6）=-√3/3∴cosx+cos（x-π/3）=cosx+cosxcosπ/3+sinxsinπ/3=cosx+（1/2）cosx+（√3/2）sinx=（3/2）cosx+（√3

a为锐角sina=4/5tana=3/4a为钝角sina=-4/5tana=-3/4由(sina)^2+(cosa)^2=1和cosa=3/5可求出sina的两个值tana=sina/cosa

cosacosπ/6+sinasinπ/6+sina=4/5√3√3/2cosa+1/2sina+sina=4/5√3√3/2cosa+3/2sina=4/5√31/2cosa+√3/2sina=4/

cos(x-π/6)=-√3/3cosx+cos(x-π/3)=cos(x-π/6+π/6)+cos(x-π/6-π/6)=cos(x-π/6)cosπ/6-sin(x-π/6)sinπ/6+cos(

因为cos(a+b)=cosacosb-sinasinbcos(a-b)=cosacosb+sinasinb相加得cos(a+b)+cos(a-b)=2cosacosb即cosacosb=[cos(a

sinθ+cosθ=负五分之根号10平方得(sinθ+cosθ)²=2/5sin²a+2sinacosa+cos²a=2/51+2sinacosa=2/5sinacosa

cosa=4/5cos(a+b)=-16/25如果是锐角(如果不是,则出题的有毛病),则:cos(a+β)=-16/25,sin(a+β)=√(1-cos^2(a+β))=3(根号41)/25a为锐角

再问：能说一下每部详细步骤和原因吗

锐角则cosα>0因为sin²α+cos²α=1sinα=3/5所以cosα=4/5tanα=sinα/cosα=3/4

17π/12＜x＜7π/4,得5π/3＜x+π/4＜2πcos(x-π/4)=cos[(x+π/4)-π/2]=sin(x+π/4)=-√[1-sin²(x+π/4)]=-√[1-(3/5)

sinα=3/5,cosα=√(1-sin²α)=√(1-9/25)=4/5cos（α+β）=cosαcosβ-sinαsinβ=(4/5)cosβ-(3/5)sinβsinβ=√(1-co

sinα=3/5cosα=-4/5cos(2α-60°)=cos(2α)cos60+sin(2α)sin60=(2cos^2α-1)*1/2+2sinαcosα*√3/2=7/50+24√3/50=(

cos2b=2cosb平方-1=3/5COSB平方等于4/5cosb四方加sinb四方=cosb平方的平方加（1-cosb平方）平方等于16/25+1/25=17/25

sin(x-y)cosx-cos(x-y)sinx=sin[(x-y)-x]=sin(-y)=-siny=3/5siny=-3/5sin²y+cos²y=1所以cos²y

sina/2=3/5>0cosa/2=-4/5再问：由题2kπ+3π/4