(x-3)(x 2)=6怎么解
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(x-1)(x+1)]=[7/x
3/x2=1/x2-x即3*2-3x=x*22x*2=3Xx=0(舍去)x=3/2
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
(1)x2+4x+4=1+4,∴(x+2)2=5,∴x+2=±5,∴x1=5-2,x2=-5-2;(2)整理得2x(x+3)-(x+3)=0,∴(x+3)(2x-1)=0,∴x+3=0或2x-1=0,
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
7/(X2+X)+3/(X2-X)=6/(X2-X),去分母,等式两端同时乘X(X+1)(X-1):7(X-1)+3(X+1)=6(X+1),7X-7+3X+3=6X+6,7X+3X-6X=6+7-3
4x+24-2x=382x=14x=7再问:亲,请问24怎么来的再答:12*2再答:(12-x)*2=24-2x再问:哦,谢谢
2x+5x+3+4-x/2+2x+x-2=019x/2=-5x=-19/10检验:带入x是、原式=0
(x2-x)=3(x2+x)x2-x=3x2+3xx2-3x2-x-3x=0-2x2-4x=0-2x(x+2)=0x1=0x2=-2
1/(x²-5x+6)-1/(x²-4x+3)+1/(x²-3x+2)=1/(x-1)1/[(x-2)(x-3)]-1/[(x-1)(x-3)]+1/[(x-1)(x-2
7/(x+x2)-3/(x-x2)=6/(x2-1)两边同乘以x(x+1)(x-1),得7(x-1)+3(x+1)=6x7x-7+3x+3=6x10x-6x=3-74x=-4x=-1经检验x=-1是增
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31)x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
解方程:x2-6x+2x2-6x=3x2-3x-3-9x=-3x=1/3解不等式:2x3-6x2+4x2-4x≥2x3-2x2+5x-39x-3≤0x≤1/3
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
令(x^2-1)/x=t3/t+t/2=5/2t^2-5t+6=0t=2或t=3即:(x^2-1)/x=2或(x^2-1)/x=3x^2-2x-1=0或x^2-3x-1=0x=1±√2或x=(3±√1
x2-5x+8=0a=1,b=-5,c=8∴△=b²-4ac=(-5)²-4×1×8=25-32=-7
X-18=(X-25)x2X-18=2X-502X-X=50-18X=32