已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/04/25 08:07:13
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
已知x-y=1,则y=x-1,x=y+1
{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y
=(x²+4xy+4y²+2x²+9xy+4y²-3x²+3y²)÷y
=(x²+2x²-3x²+4xy+9xy+4y²+4y²+3y²)÷y
=(13xy+11y²)÷y
=13x+11y
=13x+11(x-1)
=13x+11x-11
=24x-11
或
=13(y+1)+11y
=13y+13+11y
=24y+13
{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y
=(x²+4xy+4y²+2x²+9xy+4y²-3x²+3y²)÷y
=(x²+2x²-3x²+4xy+9xy+4y²+4y²+3y²)÷y
=(13xy+11y²)÷y
=13x+11y
=13x+11(x-1)
=13x+11x-11
=24x-11
或
=13(y+1)+11y
=13y+13+11y
=24y+13
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
已知x和y满足x+3y+|3x-y|=19,2x+y=6,求x,y的值
已知x:y=2:3,且二分之2x+y-1,求x、y的值
已知2x-y=-6,求代数式[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4y的值.
已知2x-y=-6,求代数式[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4y的值
x(x-y)-y(y-x)+(x-y)²因式分解
已知2x-y/x+3y=2,求代数式﹙4x-2y/x+3y﹚-﹙4x+12y/2x-y﹚的值
已知(2x-1)²+|4x-y|=0,求x+y的值
1、已知实数x、x满足x²+y²-xy+2x-y+1=0,试求x、y的值.
已知2x-y=-6,求代数式[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4x的值.
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
已知2y-x/7x+5y=2/3且y≠0,求x/y的值