搜搜做题作业网计算(4x^2-2x^3+6x)/(-2x)-(x-1)^2y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/
来源：学生作业帮 编辑：搜搜做题作业网作业帮 分类：数学作业 时间：2024/04/26 03:19:31
计算
(4x^2-2x^3+6x)/(-2x)-(x-1)^2
y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/y-3)
(4x^2-2x^3+6x)/(-2x)-(x-1)^2
y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/y-3)
原式=-2x+x^2-3-x^2+2x-1
=-4
原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)
=(y-2)/(y-3)+(y+2)/(y+1)
=(y^2-y-2+y^2-y-6)/(y-3)(y+1)
=(2y^2-2y-8)/(y-3)(y+1)
=-4
原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)
=(y-2)/(y-3)+(y+2)/(y+1)
=(y^2-y-2+y^2-y-6)/(y-3)(y+1)
=(2y^2-2y-8)/(y-3)(y+1)
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
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