Solve the inequality (x-4)(3-x)>0

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/05/26 05:10:47

Solve the inequality (x-4)(3-x)>0
find the set of values of x for which 2x2+3x+2大于或等于4
Rewrite 3x2+9x+2 as a(x+p)2次平方+q by completing the square and hence.sketch the curve y=3x2+9x+2 stating clearly the co-ordinates of the turning point and y_ intercept.
没人看得懂吗?第一题就是不等式 (x-4)(3-x)>0
第二题就找出值 2x2+3x+2大于或等于4
第三题就算了,只是不敢确定
答案我知道是 X＞4或X＜3

记住口诀!小于取中间,大于取两边!第一题：(x-4)(3-x)>0.首先,使不等式左边未知数系数化为正数,即 (x-4)(x－3)＜0.3＜X＜4
第二题：2x2+3x+2大于或等于4.即4＋3X＋2≥4.X≥－2／3

Solve the given nonlinear inequality.Write the solution set The sum of all such integers x thatsatisfy inequality 2≤丨2x- 用mathematica求解方程Solve[8 Cos[0.5x] - 4x Sin[0.5x] == 0, x] 出不 matlab新手求解3：solve函数.我输入solve('x^3+5*x-8'),结果求得三个解:. matlab solve函数 xmaxr=solve(dydx,x) >> [x,y] = solve('(5/6)*(1+x)^3-(10/6)*(2.5+x)^3+0.09*x^3+29 用mathematica求Solve[{a*x (1 - x/k) - (c*x)/(m + x) y = 0, 1 - A function f is such that f(x)=ln(5x-10) solve f(x)=0 matlab运行syms x；s=solve(x^3+cos(x)) 为什么结果总是[ empty sym ]啊, solve:log(x)+log(2x)=2 cos(x)*cosh(x)+1=0 solve('cos(t)*cosh(t)+1=0') ans = 1.87510 how to graph inequality in the coordinate plane