因式分解 9.6 学与练若n^2+3n=1,求n(n+1)(n+2)+1
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因式分解 9.6 学与练若n^2+3n=1,求n(n+1)(n+2)+1
n^2+3n=1
n²+3n-1=0
n=(-3±√13)/2
n(n+1)(n+2)+1
=n(n²+3n+2)+1
=n(1+2)+1
=3n+1
=3*(-3±√13)/2+1
=(-7±3√13)/2
再问: 没学开方
再答: 那这题你做不了啊
n²+3n-1=0
n=(-3±√13)/2
n(n+1)(n+2)+1
=n(n²+3n+2)+1
=n(1+2)+1
=3n+1
=3*(-3±√13)/2+1
=(-7±3√13)/2
再问: 没学开方
再答: 那这题你做不了啊
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