若xy/x+y=2,则3x-xy+3y/-x+3xy-y=
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若xy/x+y=2,则3x-xy+3y/-x+3xy-y=
原题是 xy/(x+y)=2 求(3x-xy+3y)/(-x+3xy-y)吗 如果是 那么计算如下
由xy/(x+y)=2 得x+y=xy/2
(3x-xy+3y)/(-x+3xy-y
=[3(x+y)-xy]/[-(x+y)+3xy]
=[3xy/2-xy]/[-xy/2+3xy]
=(xy/2)/(5xy/2)
=xy/2×2/5xy
=1/5
由xy/(x+y)=2 得x+y=xy/2
(3x-xy+3y)/(-x+3xy-y
=[3(x+y)-xy]/[-(x+y)+3xy]
=[3xy/2-xy]/[-xy/2+3xy]
=(xy/2)/(5xy/2)
=xy/2×2/5xy
=1/5
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