计算:(1/a+1/b)•(ab)/a²+2ab+b²
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计算:(1/a+1/b)•(ab)/a²+2ab+b²
![计算:(1/a+1/b)•(ab)/a²+2ab+b²](/uploads/image/z/20005020-36-0.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%881%2Fa%2B1%2Fb%EF%BC%89%26%238226%3B%28ab%29%2Fa%26sup2%3B%2B2ab%2Bb%26sup2%3B)
(1/a+1/b)•(ab)/a²+2ab+b²
=(a+b)/ab • (ab)/(a+b)^2
= 1/(a+b)
=(a+b)/ab • (ab)/(a+b)^2
= 1/(a+b)
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