[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程

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12x+6y=12z+4x=12y+3z
分成两个等式:
x+y/2 = y+z/4
=>4x+2y= 4y+z
=>4x=2y+z(一）
x+y/2=z+x/3
=>6x+3y = 6z +2x
=>4x = 6z-3y(二）
结合（一）（二）
6z-3y = 2y+z
5z = 5y
z = y
代入（二）
4x = y ×6 - 3y
4x = 3y
x = 3/4y
3/4 y + y + y = 27
3y + 4y + 4y = 108
11y = 108
y = 108/11
z = 108/11
x = 81/11

解三元一次方程（要有过程） x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 2x+3y-4z=0.,3x+4y+5z=0,则x+y+z/x-y+z详细的解题过程 (x+y-z)(x-y+z)= x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 求解三元一次方程组：｛x+y/2=y+z/3=z+x/4 x+y+z=27 x/2=y/3=z/5 x+3y-z/x-3y+z 急!用加减消元法做!要有详细过程! x+3y+z=-1,2x-y+3z=7,3x+y+2z=3 解三元一次方程组：（要有过程）{x+y-z=0,x+2y+z=13,2x-3y+2z=5 X+Y+Z=? 三元方程求救要过程2x+3y+z=383x+4y+2z=564x+5y+z=66x:y=5:3x:z=7:32x-y-z x+y-z=6 x-3y+2z=0 3x+2y-z=0 求x、y、z 要过程