已知x1+x2=3,x1x2=1,求(x2+1)/(x1+1)+(x1+1)/(x2+1)的值
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已知x1+x2=3,x1x2=1,求(x2+1)/(x1+1)+(x1+1)/(x2+1)的值
![已知x1+x2=3,x1x2=1,求(x2+1)/(x1+1)+(x1+1)/(x2+1)的值](/uploads/image/z/19782271-55-1.jpg?t=%E5%B7%B2%E7%9F%A5x1%2Bx2%3D3%2Cx1x2%3D1%2C%E6%B1%82%EF%BC%88x2%2B1%EF%BC%89%2F%EF%BC%88x1%2B1%EF%BC%89%2B%28x1%2B1%29%2F%28x2%2B1%29%E7%9A%84%E5%80%BC)
(x2+1)/(x1+1)+(x1+1)/(x2+1)
=(x2+x1x2)/(x1+x1x2)+(x1+x1x2)/(x2+x1x2)
=x2(x1+x2)/[x1(x1+x2)]+x1(x1+x2)/[x2(x1+x2)]
=x2/x1+x1/x2
=(x2^+x1^2)/(x1x2)
=[(x1+x2)^2-2x1x2]/(x1x2)
=9-2
=7
=(x2+x1x2)/(x1+x1x2)+(x1+x1x2)/(x2+x1x2)
=x2(x1+x2)/[x1(x1+x2)]+x1(x1+x2)/[x2(x1+x2)]
=x2/x1+x1/x2
=(x2^+x1^2)/(x1x2)
=[(x1+x2)^2-2x1x2]/(x1x2)
=9-2
=7
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2)
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(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,
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