sin(x+y)=1/2 ,sin(x-y)=1/3,求tanx/tany的值
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sin(x+y)=1/2 ,sin(x-y)=1/3,求tanx/tany的值
![sin(x+y)=1/2 ,sin(x-y)=1/3,求tanx/tany的值](/uploads/image/z/19750576-40-6.jpg?t=sin%EF%BC%88x%2By%29%3D1%2F2+%2Csin%28x-y%29%3D1%2F3%2C%E6%B1%82tanx%2Ftany%E7%9A%84%E5%80%BC)
2sinxcosy=sin(x+y)+sin(x-y)=5/6
2cosxsiny=sin(x+y)-sin(x-y)=1/6
两式相除得所求=5
再问: 谢谢了
2cosxsiny=sin(x+y)-sin(x-y)=1/6
两式相除得所求=5
再问: 谢谢了
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