求不定积分(见图)求过程,
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求不定积分(见图)求过程,
∫dx/(x^2-4)
=∫dx/(x+2)(x-2)
=∫dx1/4*[1/(x-2)-1/(x+2)
=1/4∫dx/(x-2)-1/4∫dx/(x+2)
=1/4ln|x-2|-1/4ln|x+2|+C
=1/4ln|(x-2)/(x+2)| +C
=∫dx/(x+2)(x-2)
=∫dx1/4*[1/(x-2)-1/(x+2)
=1/4∫dx/(x-2)-1/4∫dx/(x+2)
=1/4ln|x-2|-1/4ln|x+2|+C
=1/4ln|(x-2)/(x+2)| +C