yua圆
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/16 18:52:26
解题思路: 求出圆心和半径,比较半径和2√2;要求圆上至少有三个不同的点到直线l:ax+by=0的距离为2√2 ,则圆心到直线的距离应小于等于 √2 ,用圆心到直线的距离公式,可求得结果.
解题过程:
见附件
最终答案:略
解题过程:
见附件
最终答案:略
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