x=a(t-sin t),y=a(1-cos t)(a>0) 求它的弧微分怎么求
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x=a(t-sin t),y=a(1-cos t)(a>0) 求它的弧微分怎么求
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![x=a(t-sin t),y=a(1-cos t)(a>0) 求它的弧微分怎么求](/uploads/image/z/19565236-28-6.jpg?t=x%3Da%28t-sin+t%29%2Cy%3Da%281-cos+t%29%28a%3E0%29+%E6%B1%82%E5%AE%83%E7%9A%84%E5%BC%A7%E5%BE%AE%E5%88%86%E6%80%8E%E4%B9%88%E6%B1%82)
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