AB and CD are perpendicular to line BD with AB = 997,BD = 20

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AB and CD are perpendicular to line BD with AB = 997,BD = 2012 and CD = 512.If E is a point on BD,what is the shortest possible distance forAE + EC?

作C点关于BD的对称点C',则有EC=EC', 连接AC' 交BD于点P
:. AE+EC=AE+EC'
根据三角形边长定理,当AEC'三点共线时,AE+EC'最短.

如图,已知AB⊥BD,AC⊥AB,AB=AC,求证:BD=CD 已知：如图,AB=BD,AC⊥CD,AB=AC.求证：BD=CD 已知AB⊥BD,AC⊥CD,AB=AC,求证BD=CD 如下图①,已知AB⊥BD,ED⊥BD,AB=CD,AC=CE. 如图,已知AB⊥BD,CD⊥BD,AB=DC,求证AD‖BC 如图所示,AB=CD,BD=AC,AB//CD.求证,AB⊥BC,全等三角形! 如图,已知角A=90度,AC=20,AB=10,延长AB至点D,使AC+AB=CD+BD,求BD长已知:如图,AB⊥BD,CD⊥DB,AD=BC 求证:AB=CD 等腰梯形ABCD中,AB//CD,AB>CD,AD=BC,BD平分如图,已知AB∥CD,AB=CD,求证：AC与BD平分. 如图AC、BD相交于点O,AC=BD,AB=CD.急) 已知：如图，AB⊥BD，CD⊥BD，AD=BC．求证：