lim(x->0)(cosx) ^[(cotx) ^2]
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/25 18:32:33
lim(x->0)(cosx) ^[(cotx) ^2]
![lim(x->0)(cosx) ^[(cotx) ^2]](/uploads/image/z/19009517-5-7.jpg?t=lim%28x-%3E0%EF%BC%89%28cosx%29+%5E%EF%BC%BB%EF%BC%88cotx%EF%BC%89+%5E2%EF%BC%BD)
lim(x->0)(cosx) ^[(cotx) ^2]
=e^[lim (cotx)^2*lncosx]
=e^[lim (cotx)^2*ln(1+cosx-1)]
=e^[lim (cotx)^2*(cosx-1)]
=e^[lim (1/x^2)(-1/2)x^2]
=e^(-1/2)
=e^[lim (cotx)^2*lncosx]
=e^[lim (cotx)^2*ln(1+cosx-1)]
=e^[lim (cotx)^2*(cosx-1)]
=e^[lim (1/x^2)(-1/2)x^2]
=e^(-1/2)
lim X=0时(1-COSX)COTX的极限.
求lim(x *cotx)x趋于0的极限
高数求极限...lim(lnx)/(cotx) x-0+
x趋向于0+,lim(cotx)^1/(lnx)
lim(x趋向于0)(1-cosx)/x^2
(tanx+cotx)*cos的平方x=?A.tanx B.sinx C.cosx D.cotx
求lim(1+tanx)^cotx,x→0的极限
lim(x趋向于0+)(cotx)^tanx 答案是1,求助〜
已知,sinx+cosx=1/5,x属于(0,兀),则cotx的值是?
lim(X一>0)(COSX)^[(1/SinX)^2]=
高数泰勒公式求极限lim(x→0)1/x(1/x-cotx)
计算 lim(x-0) [1-cosx]/[xln(1+x)]