求值:[log6(3)]^2+log6(18)/log2(6)很着急.
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求值:[log6(3)]^2+log6(18)/log2(6)很着急.
我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
第三步少了【log6(2)】^2
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
第三步少了【log6(2)】^2
[(1-log6 3)^2+log6 2-log6 18]/log6 4
求值:(log6 2)²+log6 3*log 6 2+log6 3,应该怎么算?
[log6(4)/log6(36)]/[log6(6)/log6(18)]求值的详细过程,
log6 2*log6 18+log6 81/4log3 6
(log6 3)^2+log6 18乘以log6 2
[(1-log6 3)^2+log6 2·log6 18]·log4 6
(log6(2))^2+log6(2)*log6(3)+log6(18)的值
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)
{(1-log6 3)^2+log6 2*log6 18}/log6 4 等于多少,请写出就算过程,
((1-log6(3))²+log6(2)*log6(18))/log6(4)
[(1-log6 3)²+log6 2×log6 18]/log6 4
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2