sin^3(3x)求导
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sin^3(3x)求导
{[sin(3x)]^3}'
= 3{[sin(3x)]^2}*[sin(3x)]'
= 3{[sin(3x)]^2}*[cos(3x)]*(3x)'
= 3{[sin(3x)]^2}*[cos(3x)]*3
= 9{[sin(3x)]^2}*[cos(3x)].
= 3{[sin(3x)]^2}*[sin(3x)]'
= 3{[sin(3x)]^2}*[cos(3x)]*(3x)'
= 3{[sin(3x)]^2}*[cos(3x)]*3
= 9{[sin(3x)]^2}*[cos(3x)].