化简f(x)=cos(2x-π/3)-cos2x
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化简f(x)=cos(2x-π/3)-cos2x
和差化积公式
cos(a)-cos(b) = -2sin[(a+b)/2]sin[(a-b)/2]
f(x)=cos(2x-π/3)-cos2x=-2sin(2x-π/6)sin-π/6
=sin(2x-π/6)
cos(a)-cos(b) = -2sin[(a+b)/2]sin[(a-b)/2]
f(x)=cos(2x-π/3)-cos2x=-2sin(2x-π/6)sin-π/6
=sin(2x-π/6)
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