设函数f(x)在点x=2处可导,且f'(2)=2,则limh→0 f(2+h)-f(2)/2h =( ) A1/2 B1
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设函数f(x)在点x=2处可导,且f'(2)=2,则limh→0 f(2+h)-f(2)/2h =( ) A1/2 B1 C2 D4
limh→0 f(2+h)-f(2)/2h ,是除以2h,不是h啊
limh→0 f(2+h)-f(2)/2h ,是除以2h,不是h啊
![设函数f(x)在点x=2处可导,且f'(2)=2,则limh→0 f(2+h)-f(2)/2h =( ) A1/2 B1](/uploads/image/z/18546732-36-2.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E7%82%B9x%3D2%E5%A4%84%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%27%282%29%3D2%2C%E5%88%99limh%E2%86%920+f%282%2Bh%29-f%282%29%2F2h+%3D%28+%29+A1%2F2+B1)
选D
这不是导数的定义吗? 除以2h是导数除以2
![](http://img.wesiedu.com/upload/a/8e/a8e4a9893147e4530247f756e900e176.jpg)
这不是导数的定义吗? 除以2h是导数除以2
![](http://img.wesiedu.com/upload/a/8e/a8e4a9893147e4530247f756e900e176.jpg)
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