cosα(2secα+tanα)(secα-2tanα)+3tanα
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/24 07:37:45
cosα(2secα+tanα)(secα-2tanα)+3tanα
![cosα(2secα+tanα)(secα-2tanα)+3tanα](/uploads/image/z/18111883-67-3.jpg?t=cos%CE%B1%282sec%CE%B1%2Btan%CE%B1%29%28sec%CE%B1-2tan%CE%B1%29%2B3tan%CE%B1)
cosα(2secα+tanα)(secα-2tanα)+3tanα
=cosα(2secα*secα-4secα*tanα+secα*tanα-2tanα*tanα)+3tanα
=cosα[2(secα*secα-tanα*tanα)-4secα*tanα+secα*tanα]+3tanα
=cosα(2-3secα*tanα)+3tanα
=2cosα-3cosα*secα*tanα+3tanα
=2cosα-3tanα+3tanα
=2cosα
=cosα(2secα*secα-4secα*tanα+secα*tanα-2tanα*tanα)+3tanα
=cosα[2(secα*secα-tanα*tanα)-4secα*tanα+secα*tanα]+3tanα
=cosα(2-3secα*tanα)+3tanα
=2cosα-3cosα*secα*tanα+3tanα
=2cosα-3tanα+3tanα
=2cosα
tanα+secα-1/tanα-secα+1=1+sinα/cosα
求证:(tanα+secα-1)/(tanα-secα+1)=(1+sinα)/cosα
求证:(1+secα+tanα)/(1+secα+tanα)=(1+sinα)/cosα
求证1+sinα/cosα=tanα+secα-1/tanα-secα+1
化简:secα√(1+tan^2α)+tanα√(csc^2-1)
证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α
已知tan^2α+cot^2α+sec^2α+csc^2α=7,则sinαcosα
(tanα+cotα)/ (secα*cscα)=?
tanα+cotα=secα·cscα
化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc
求证:(tanα -cotα )/(secα -cscα )=sinα +cosα
求证明三角函数等式啊 1.tanα+cosα/(1+sinα)=secα 2.cotα/(1-tanα)+tanα/(1