x=6y,x-2×2=10(y-2z),x+2×6=3(y+6z)
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x=6y,x-2×2=10(y-2z),x+2×6=3(y+6z)
x=84 y=14 z=3
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值
已知x^3+y^3-6x+2y+z+3+10=0,求(x-y+z)(x+y-z)的值.(z+3)是绝对值
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
2x+3y+z=11,3x+y-z=2,x+y+z=6求解
已知x,y,z为实数,满足x+2y-z=6x-y+2z=3