已知f(x)=sin^2πx/4-cos^2πx/4*cosπx/4,则f(2014)
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已知f(x)=sin^2πx/4-cos^2πx/4*cosπx/4,则f(2014)
f(x)=[sin(πx/4)]^2-[cos(πx/4)]^2*cos(πx/4)
f(2014)
=[sin(1007π/2)]^2-[cos(1007π/2)]^2*cos(1007π/2)
=[sin(3π/2)]^2-[cos(3π/2)]^2*cos(3π/2)
=1 -0
=1
f(2014)
=[sin(1007π/2)]^2-[cos(1007π/2)]^2*cos(1007π/2)
=[sin(3π/2)]^2-[cos(3π/2)]^2*cos(3π/2)
=1 -0
=1
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