如果x^2-3x+1=0,试求2x^5-5x^4+2x^3-8x^2+3x=?
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如果x^2-3x+1=0,试求2x^5-5x^4+2x^3-8x^2+3x=?
![如果x^2-3x+1=0,试求2x^5-5x^4+2x^3-8x^2+3x=?](/uploads/image/z/17982360-0-0.jpg?t=%E5%A6%82%E6%9E%9Cx%5E2-3x%2B1%3D0%2C%E8%AF%95%E6%B1%822x%5E5-5x%5E4%2B2x%5E3-8x%5E2%2B3x%3D%3F)
2x^5-5x^4+2x^3-8x^2+3x
=2x^3(x^2-3x+1)+x^4-8x^2+3x
=x^4-8x^2+3x
=x^4-7x^2-(x^2-3x)
=x^4-7x^2-1
=x^2(x^2-3x+1)+3x^3-8x^2-1
=3x^3-8x^2-1
=3x(x^2-3x+1)+x^2-3x-1
=x^2-3x-1
=-1-1
=-2
=2x^3(x^2-3x+1)+x^4-8x^2+3x
=x^4-8x^2+3x
=x^4-7x^2-(x^2-3x)
=x^4-7x^2-1
=x^2(x^2-3x+1)+3x^3-8x^2-1
=3x^3-8x^2-1
=3x(x^2-3x+1)+x^2-3x-1
=x^2-3x-1
=-1-1
=-2
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