根号2sin(πx/8+π/4)+根号2sin(πx/8+3π/4)化简
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/04 14:08:00
根号2sin(πx/8+π/4)+根号2sin(πx/8+3π/4)化简
原式=根号2sin(πx/8+π/4)+根号2sin(π/2 + πx/8+ π/4)
=根号2sin(πx/8+π/4)+根号2cos(πx/8+ π/4)
=2*[根号2/2 *sin(πx/8+π/4)+ 根号2/2 *cos(πx/8+ π/4)]
=2sin(πx/8+π/4 +π/4)
=2sin(πx/8 + π/2)
=2cos(πx/8)
=根号2sin(πx/8+π/4)+根号2cos(πx/8+ π/4)
=2*[根号2/2 *sin(πx/8+π/4)+ 根号2/2 *cos(πx/8+ π/4)]
=2sin(πx/8+π/4 +π/4)
=2sin(πx/8 + π/2)
=2cos(πx/8)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
化简sin(2x+π/3)-(根号3)sin²x+sinxcosx+(根号3)/2
已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x
已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x
已知向量a=(根号2sin(4/π+x)+1,-根号3),b=(根号2sin(4/π+x)-1,cos2x函数f(x)=
f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3
已知函数y=2sin(2x-π/4)-2根号2sin^2x
求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3
求证sinx-cosx=根号2sin(x-π/4)
f(x)=sin平方x+2根号3sin(x+π/4)cos(x-π/4)-cos平方x-根号3
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
已知函数f(x)=2根号3sin平方x-sin(2x-π/3)