x
原式=(x+y)• x2+y2 (x2+y2)(x+y)(x−y) = 1 x−y, 当x=2012,y=2013时,原式= 1 2012−2013=-1. 故答案为:-1.
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
1.已知1/x+1/y=-1/x+y,则y/x+x/y=?
已知x/5=y/3,则(x/x+y)+(y/x-y)-(yxy/xxx-yxy)
1、已知x=2y,则x-5y/x+y=()
已知x、y满足方程组3x+y=2013,x+3y=2012,求x-y
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已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值?
已知(x-y)/13=y/7,则(x+y)/y=
已知x²+y²-2x+4y+5=0,则(x+y)2012次方=____.
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已知x+y+2(-x-y+1)=3(1-y-x)-4(y+x-1),则x+y等于( )
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