x/(x²-x)+2=2x/(x+1)解方程←
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x/(x²-x)+2=2x/(x+1)解方程←
![x/(x²-x)+2=2x/(x+1)解方程←](/uploads/image/z/16980742-46-2.jpg?t=x%2F%28x%26%23178%3B-x%29%2B2%3D2x%2F%28x%2B1%29%E8%A7%A3%E6%96%B9%E7%A8%8B%E2%86%90)
x/(x²-x)+2=2x/(x+1)
[x/x(x-1)]+2=2x/(x+1)
1/(x-1)+2=2x/(x+1)
[ 2x/(x+1)]-[1/(x-1)]=2
[ 2x(x-1)/(x+1)(x-1)]-[(x+1)/(x+1)(x-1)]=2
2x^2-2x-x-1=2(x+1(x-1)
2x^2-3x-1=2(x^2-1)
2x^2-3x-1=2x^2-2
3x=1
x=1/3
此题主要考的是平方差公式,及分数的通分
[x/x(x-1)]+2=2x/(x+1)
1/(x-1)+2=2x/(x+1)
[ 2x/(x+1)]-[1/(x-1)]=2
[ 2x(x-1)/(x+1)(x-1)]-[(x+1)/(x+1)(x-1)]=2
2x^2-2x-x-1=2(x+1(x-1)
2x^2-3x-1=2(x^2-1)
2x^2-3x-1=2x^2-2
3x=1
x=1/3
此题主要考的是平方差公式,及分数的通分
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