问道有理数算术题-1²-【1又3/7+(-12)÷6】²×(-7/4)
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问道有理数算术题
-1²-【1又3/7+(-12)÷6】²×(-7/4)
-1²-【1又3/7+(-12)÷6】²×(-7/4)
-1²-【1又3/7+(-12)÷6】²×(-7/4)
=-1²-[10/7+(-2)]²×(-7/4)
=-1²-[- 4/7]²×(-7/4)
=-1²-16/49×(-7/4)
=-1²+4/7
=-1+4/7
=-3/7
=-1²-[10/7+(-2)]²×(-7/4)
=-1²-[- 4/7]²×(-7/4)
=-1²-16/49×(-7/4)
=-1²+4/7
=-1+4/7
=-3/7
有理数乘方的算术题,-6²×(-1又1/2)²-3³÷(-1又1/2)³×(-3
(2²+4²+6²+.+98²+100²)-(1²+3&su
1.计算:1²+4²+6²+7²=102,2²+3²+5&s
不用计算器求值1²+2²+3²+4²+5²+6²+7&sup
1²-2²+3²-4²+5²-6²+…-100²+
1÷[(-2)²×0.5²-(-2.24)÷(-2)³]-1又7/18
再求代数式(4x²-7x+6y-1)-(-2x²+3y²+2y+2x)+(-6x²
4²+3²>2*4*3,(-2)²+1²>2*(-2)*1,2²+2&
已知3既是(x-1)的算术平方根,又是(x-2y+1)的立方根,求x²-y²的平方根
(找规律)5²-3²=8*29²-7²=8*415²-3²=
小学综合思维题1、计算:1²-2²+3²-4²+5²-6²+
(1-1/2²)(1-1/3²)(1-1/4²).(1-1/10²)=?