y=(x^2·e^x)+㏑3,求dy/dx.
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y=(x^2·e^x)+㏑3,求dy/dx.
y=(x^2﹚﹙e^x)+㏑3,求dy/dx.
y=(x^2﹚﹙e^x)+㏑3,求dy/dx.
![y=(x^2·e^x)+㏑3,求dy/dx.](/uploads/image/z/16386161-41-1.jpg?t=y%3D%EF%BC%88x%5E2%C2%B7e%5Ex%EF%BC%89%2B%E3%8F%913%2C%E6%B1%82dy%2Fdx.)
解
y'=dy/dx
=(x²e^x)'+(ln3)'
=2xe^x+x²e^x+0
=2xe^x+x²e^x
y'=dy/dx
=(x²e^x)'+(ln3)'
=2xe^x+x²e^x+0
=2xe^x+x²e^x