√(1+cosθ/1-cosθ)-√(1-cosθ/1+cosθ)(π<θ<3/2π)
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√(1+cosθ/1-cosθ)-√(1-cosθ/1+cosθ)(π<θ<3/2π)
![√(1+cosθ/1-cosθ)-√(1-cosθ/1+cosθ)(π<θ<3/2π)](/uploads/image/z/16295407-7-7.jpg?t=%E2%88%9A%281%2Bcos%CE%B8%2F1-cos%CE%B8%29-%E2%88%9A%281-cos%CE%B8%2F1%2Bcos%CE%B8%EF%BC%89%EF%BC%88%CF%80%EF%BC%9C%CE%B8%EF%BC%9C3%2F2%CF%80%EF%BC%89)
√(1+cosθ/1-cosθ)-√(1-cosθ/1+cosθ)
=√(1+cosθ)^2/(sinθ)^2-√(1-cosθ)^2/(sinθ)^2
= - (1+cosθ)/sinθ+(1-cosθ)/sinθ
= -2cosθ/sinθ
=-2cotθ
懒的检查 自己再检查看看...
=√(1+cosθ)^2/(sinθ)^2-√(1-cosθ)^2/(sinθ)^2
= - (1+cosθ)/sinθ+(1-cosθ)/sinθ
= -2cosθ/sinθ
=-2cotθ
懒的检查 自己再检查看看...
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