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已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+

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已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2的值
已知x^2+4y^2-2x-2x+8y+5=0,求x^2-y^2/2x^2+xy-y^2*2y-y/xy-y/(x^2+
x²+4y²-2x+8y+5=0
(x-1)²+(2y+2)²=0
得 x=1,y=-1
则 x²-y²/2x²+xy-y²*2y-y/xy-y/(x²+y²/y)²
=1-1/2-1+2-1+1/4
=1/2+1/4
=3/4
再问: 已知x^2+4y^2-2x-2x+8y+5=0,求x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2的值
再答: x^2+4y^2-2x+8y+5=0 (x-1)²+(2y+2)²=0 得 x=1,y=-1 则 x^4-y^4/2x^2+xy-y^2*2y-y/xy-y/(x^2+y^2/y)^2 =1-1/2-1+2-1+1/4 =3/4