2(x-3)²=x²-9 用因式分解法解方程
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2(x-3)²=x²-9 用因式分解法解方程
答:
2(x-3)²=x²-9
2(x-3)²-(x²-3²)=0
2(x-3)²-(x-3)(x+3)=0
(x-3)*[2(x-3)-(x+3) ]=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
解得:x1=3,x2=9
2(x-3)²=x²-9
2(x-3)²-(x²-3²)=0
2(x-3)²-(x-3)(x+3)=0
(x-3)*[2(x-3)-(x+3) ]=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
解得:x1=3,x2=9