设等比数列an的公比是q=2,前an项的和为sn,则s4/a2=?
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设等比数列an的公比是q=2,前an项的和为sn,则s4/a2=?
![设等比数列an的公比是q=2,前an项的和为sn,则s4/a2=?](/uploads/image/z/15925823-71-3.jpg?t=%E8%AE%BE%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97an%E7%9A%84%E5%85%AC%E6%AF%94%E6%98%AFq%3D2%2C%E5%89%8Dan%E9%A1%B9%E7%9A%84%E5%92%8C%E4%B8%BAsn%2C%E5%88%99s4%2Fa2%3D%3F)
sn=(1(1-q^n))/(a1*q)
a2=a1*q
s4/a2=(a1(1-q^n))/(a1×q(1-q))=(1-q^n)/(q(1-q))=(2^n-1)/2
a2=a1*q
s4/a2=(a1(1-q^n))/(a1×q(1-q))=(1-q^n)/(q(1-q))=(2^n-1)/2
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