关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X
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关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X+3)],
![关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X](/uploads/image/z/15829306-34-6.jpg?t=%E5%85%B3%E4%BA%8E%E6%95%B0%E5%AD%A6%E5%8C%96%E7%AE%80%E9%A2%98%2C%E6%80%8E%E4%B9%88%E4%BB%8E%5B1%2F%EF%BC%88x%2B1%EF%BC%89%5D%2A%7B%EF%BC%88x-1%EF%BC%89%2F%EF%BC%88x%2B3%EF%BC%89%7D%2B1%5D%E5%8C%96%E7%AE%80%E5%88%B0%5B1%2F%EF%BC%88x%2B1%EF%BC%89%5D%2A%5B2%28X%2B1%29%2F%28X)
[1/(x+1)]*{(x-1)/(x+3)}+1]
=[1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}
=[1/(x+1)]*[2(X+1)/(X+3)]
再问: { [(x-1)+(x+3)] /(x+3)} 怎么等于[2(X+1)/(X+3)]
再答: 1/(x+1)]*{(x-1)/(x+3)+1} =1/(x+1)]*{(x-1)/(x+3)+(x+3)/(x+3)} =1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)} =1/(x+1)]*{ [2x+2] /(x+3)} =1/(x+1)]*[2(X+1)/(X+3)] 你那个大括号应该位置错了,在最末尾
=[1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}
=[1/(x+1)]*[2(X+1)/(X+3)]
再问: { [(x-1)+(x+3)] /(x+3)} 怎么等于[2(X+1)/(X+3)]
再答: 1/(x+1)]*{(x-1)/(x+3)+1} =1/(x+1)]*{(x-1)/(x+3)+(x+3)/(x+3)} =1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)} =1/(x+1)]*{ [2x+2] /(x+3)} =1/(x+1)]*[2(X+1)/(X+3)] 你那个大括号应该位置错了,在最末尾
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