e^[(3x+9)^(1/2)]dx
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e^[(3x+9)^(1/2)]dx
令√(3x+9)=u,则:3x+9=u^2,∴3dx=2udu,∴dx=(2/3)udu.
∴∫[e^√(3x+9)]dx
=(2/3)∫ue^udu=(2/3)∫ud(e^u)=(2/3)ue^u-(2/3)∫(e^u)du
=(2/3)√(3x+9)e^√(3x+9)-(2/3)e^u+C
=(2/3)√(3x+9)e^√(3x+9)-(2/3)e^√(3x+9)+C
∴∫[e^√(3x+9)]dx
=(2/3)∫ue^udu=(2/3)∫ud(e^u)=(2/3)ue^u-(2/3)∫(e^u)du
=(2/3)√(3x+9)e^√(3x+9)-(2/3)e^u+C
=(2/3)√(3x+9)e^√(3x+9)-(2/3)e^√(3x+9)+C
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