求函数y=log(2)4x*log(2)2x在(1/4
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求函数y=log(2)4x*log(2)2x在(1/4
y=log(2)4x*log(2)2x
=[2+log(2)x]*[1+log(2)x]
=[log(2)x]^2+3*log(2)x+2
=[log(2)x+3/2]^2-1/4
因为1/4
=[2+log(2)x]*[1+log(2)x]
=[log(2)x]^2+3*log(2)x+2
=[log(2)x+3/2]^2-1/4
因为1/4
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