已知x/y=2/3,求x²-y²/xy÷[(x+y)(x-y/x)³]÷x/y²
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已知x/y=2/3,求x²-y²/xy÷[(x+y)(x-y/x)³]÷x/y²的值
y=3x/2
=(x+y)(x-y)/xy*[x^3/(x+y)(x-y)^3]*(y^2/x)
=xy/(x-y)^2
=(3x^2/2)/(-x/2)^2
=(3/2)/(1/4)
=6
再问: 谢谢了
=(x+y)(x-y)/xy*[x^3/(x+y)(x-y)^3]*(y^2/x)
=xy/(x-y)^2
=(3x^2/2)/(-x/2)^2
=(3/2)/(1/4)
=6
再问: 谢谢了
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