已知sin(π/4+x)=12/13(π/4
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已知sin(π/4+x)=12/13(π/4
![已知sin(π/4+x)=12/13(π/4](/uploads/image/z/15107973-69-3.jpg?t=%E5%B7%B2%E7%9F%A5sin%28%CF%80%2F4%2Bx%29%3D12%2F13%28%CF%80%2F4)
cos2x / cos(π/4-x)=cos2x/sin(π/2-π/4+x)
=(cos2x)/sin(π/4+x)
sin(π/4+x)=12/13
cos(π/4+x)=7/13(π/4
再问: sin(π/4+x)=12/13 cos(π/4+x)=7/13(π/4
=(cos2x)/sin(π/4+x)
sin(π/4+x)=12/13
cos(π/4+x)=7/13(π/4
再问: sin(π/4+x)=12/13 cos(π/4+x)=7/13(π/4
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