一个多项式除以2x^2y的商为
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/05 16:10:52
若一个多项式除以2x的平方-3,得到的商为7x-4,余式为-5x+2,多项式=(2x²-3)(7x-4)-5x+2=14x³-8x²-21x+12-5x+2=14x
(3x^2-2x+4)(2x+6)+3x-1=6x^3+14x^2-x+23这个多项式为6x^3+14x^2-x+23
(x+2)(x^2+2x-3)+5x+6=x^3-2x
(x^2-2x+3)(x+1)+2x-5=(x^2-2x+1+2)(x+1)+2x-5=[(x-1)^2+2](x+1)+2x-5=(x-1)^2(x+1)+2(x+1)+2x-5=(x-1)^2(x
2x³-4x²-1=A(2x)+x-1;2Ax=2x³-4x²-1-x+1;A=(2x³-4x²-x)/(2x);如果本题有什么不明白可以追
2x³-4x²-1=A×2x+(x-1)所以A=[(2x³-4x²-1)-(x-1)]/2x=(2x³-4x²-1-x+1)/2x=(2x&
多项式2x²-4x-1除以一个多项式A,得商式为2x,余式为x-12x²-4x-1=(2x)A+x-1(2x)A=2x²-4x-1-x+1=2x²-5x(2x)
(x-3)(3x-2)-5=3x²-2x-9x+6-5=3x²-11x+1
(2x^2+1)*(x-1)+5x=2x^3-2x^2+x-1+5x=2x^3-2x^2+6x-1
(2x³-4x²-1-x+1)÷2x=(2x³-4x²-x)÷2x=x²-2x-1/2除式=(被除式-余式)÷商式
A=x^2-2x-1/2
解题思路:被除式=商式×除式+余式 解题过程:已知多项式2x3-4x2-1除以一个多项式A,得商式为2x,余式为x-1,求这个多项式解:即这个多项式为。
[21x^5y^7+y(7x^3y^2)^2]/[-7x^5y^4]=21x^5y^7/[-7x^5y^4]+y(7x^3y^2)^2/[-7x^5y^4]=-3y^3+7x^6y^5/[-7x^5y
M=[(4x^3-6x^2-3)-(2x-3)]/3x=(4x^3-6x^2-2x)/3x=4/3x^2-2x-2/3
ax^3+bx^2+cx+d-(5x+4)=ax^3+bx^2+(c-5)x+(d-4)整除(x^2-x+2)(x^2-x+2)(ax+e)=ax^3-ax^2+2ax+ex^2-ex+2e=ax^3
设多项式为ax^3+bx^2+cx+d显然ax^3+bx^2+cx+d=(x^2-x+2)[ax+(a+b)]+(c-a+b)x+d-a-b由于余式等于5x+4所以c-a+b=5,d-a-b=4ax^
根据题意,得:(2x+6)(3x2-2x+4)+(3x-1)=6x3+14x2-x+23所以,这个多项式为:6x3+14x2-x+23.
因为4x³+2x²+2除以一个多项式A,余式为2(4x³+2x²+2-2)/A=2x²A=(4x³+2x²)/2x²=2
M÷3x²y=4x²y-1/2x+2∴M=(3x²y)(4x²y-1/2x+2)=12x^4y²-3/2x³y+6x²y
解析:被除式=除式·商式+余式由题可得:(3x^2-1)(x-2)+(x-1)=3x³-6X²-x+2+x-1=3x³-6X²+1