[5(m n)²(m-n)]³ [3(m n)²(n-m)]²

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[5(m n)²(m-n)]³ [3(m n)²(n-m)]²
已知mn/m+n=2,求3m-5mn+3n/-m+3mn-n的值

由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m

已知mn/m+n=2,求3m-5mn+3n/(-m)+3mn-n

3m-5mn+3n/(-m)+3mn-n=【3(m+n)-5mn】/【3mn-(m+n)】=【3-5mn/(m+n)】/【3mn/(m+n)-1】=【3-5x2】/【3x2-1】=-7/5

已知M+N分之MN=2,求-m+3mn-n分之3m-5mn+3n

答:mn/(m+n)=2分子分母同除以mn得:1/(1/n+1/m)=21/m+1/n=1/2(3m-5mn+3n)/(-m+3mn-n)分子分母同除以mn得:=(3/n-5+3/m)/(-1/n+3

5mn-(5mn+(2m的2次方n+(m的2次方n-3mn))-2m的2次方n)

5mn-{5mn+[2m的2次方n+(m的2次方n-3mn)]-2m的2次方n}=5mn-{5mn+[2m^2n+m^2n-3mn]-2m^2n}=5mn-{5mn+[3m^2n-3mn]-2m^2n

已知mn/m+n=2求3m-5mn+3n/-m+3mn-n

由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m+n)]/[-(m

-3m^2n/5+m^2n-mn^2

-3m^2n/5+m^2n-mn^2=(1-3/5)m^2n-mn^2=(3/5)m²n-mn²2(x-1)-3(2-3x)=2x-2-6+9x=11x-8

m+n=5 m-n=6 则mn^2-m^2n=

m+n=5m-n=6则mn^2-m^2n=mn(n-m)(m+n)^2=m^2+n^2+2mn=25(m-n)^2=m^2+n^2-2mn=364mn=25-36=-11mn=-11/4mn^2-m^

已知m-n=2,mn=-1,求(4m-5n-mn)-(2m-3n+5mn)的值

(4m-5n-mn)-(2m-3n+5mn)=4m-5n-mn-2m+3n-5mn=2m-2n-6mn=2(m-n)-6mn当m-n=2,mn=-1时,原式=2×2-6×(-1)=10已知A=2x^2

已知MN^2=-6,求-MN(M^2N^5-MN^3-N)的值

-MN(M^2N^5-MN^3-N)=-(-6)^3+(-6)^2-(-6)=258

化简m/m-n-n/m+n+mn/m^-n^

m/(m-n)-n/(m+n)+mn/(m^2-n^2)=[m(m+n)-n(m-n)]/(m+n)(m-n)+mn/(m+n)(m-n)=(m^2+mn-mn+n^2)/(m+n)(m-n)+mn/

mn(m-n)-(n-m)的因式分解

mn(m-n)-(n-m)=mn(m-n)+(m-n)=(mn+1)(m-n)

已知m.n是正整数,并且mn+3m+5n=70,求m,n

∵mn+3m+5n=70∴(m+5)(n+3)=85∵85=5X17=1X85∵m.n是正整数∴(m+5)和(n+3)只能取5和17∵m+5>5,n+3>3∴m+5=17,n+3=5∴m=12,n=2

若m+n=5,mn=-6,则(m+n)2 −4mn

∵m+n=5,mn=-6,∴(m+n)2 −4mn=52-4×(-6)=25+24=49,故答案为:49.

(a^m)^n*(-a^3m)2n/(a^mn)^5-a^2mn

(a^m)^n*(-a^3m)^2n/(amn)^5-a^2mn=a^mn*a^6mn/a^5mn-a^2mn=a^7mn/a^5mn-a^2mn=a^2mn-a^2mn=0

-2(mn-3m平方)-{m平方-5(mn-m平方)+2mn,其中m=1,n=-2

-2(mn-3m平方)-{m平方-5(mn-m平方)+2mn},其中m=1,n=-2=-2mn+6m^2-m^2+5(mn-m^2)-2mn=-2mn+6m^2-m^2+5mn-5m^2-2mn=mn

已知m-n=7,mn=2 求5n-3mn+5m+2

知m-n=7,mn=2求5n-3mn+5m+2(m+n)²=(m-n)²+4mn=49+8=57m+n=正负根号575n-3mn+5m+2=5n+5m-3mn+2=5(m+n)-3

3(m^2-mn+2n^2)-2(mn-m^2+n^2)+(5mn-4n^2+1)

原式=3m^2-3mn+6n^2-2mn+2m^2-2n^2+5mn-4n^2+1=5m^2+1再问:(2x-3y+z)-3(x-2(-z+(x-y))-(3y-5z)再答:原式=2x-3y+z-3(

若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值

已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n

若M-N=5,MN=-2,则(N-M)的平方-4MN=

(N-M)²-4MN=5²-4*(-2)=25+8=33