y三次方*(x 1的展开式存在常数
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 16:07:10
X³+Y³=(X+Y)(X²-XY+Y²)
不存在证明:由题意得导数y"=3x^2+1,则x>0时,y">0(没学过导数,就用学过的方法来证单调性)所以原函数在x>0时为增函数又f(9)=9^3+9=7381000则y=1000时,x在区间(9
(x+y)^3+(z-x)^3-(y+z)^3=[(x+y)^3-(y+z)^3]+(z-x)^3=[(x+y)-(y+z)][(x+y)^2+(x+y)(y+z)+(y+z)^2]+(z-x)^3=
xy的三次方-2x²y²+x的三次方y=xy(y²-2xy+x²)=xy(x-y)²
负的(x-y)的10次方再问:为什么呢?我要过程麻烦你了再答:后面两个(y-x)可以提负号,二次的提出来是正的,三次的是负的。会了吧~
(3x-1/x的平方开三次方)的n次方.的展开式中各项系数之和,即为x=1时,“(3x-1/x的平方开三次方)的n次方”的值故:(3-1)的n次方=128故:n=7又:(3x-1/x的平方开三次方)的
x1+x2=-b/ax1*x2=c/a代入下式x1^3+x2^3=(x1+x2)((x1+x2)^2-3*x1x2)=-b/a*(b^2/a^2-3c/a)
=xy(4x²+4xy+y²)=xy(2x+y)²
4x的三次方y+4x²y²+xy的三次方=xy(4x²+4xy+y²)=xy(2x+y)²
x+y的三次方*x+y的二次方=(x+y)^3(x+y)^2=(x+y)^(3+2)=(x+y)^5
x的三次方+8y三次方=(x+2y)(x平方-2xy+4y平方)
x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)
由韦达定理得x1+x2=3,x1*x2=3/2则x1²+x2²=(x1+x2)²-2x1*x2=9-3=6x1³+x2³=(x1+x2)(x1
-7x的三次方y的平方-21x的平方y的三次方=-7x²y²(x+3y)再问:求第二题再答:(x-y)的三次方-(y-x)的平方=(x-y)的三次方-(x-y)的平方=(x-y)&
x^3+x-y^3-y=(x^3-y^3)+(x-y)=(x-y)(x^2+xy+y^2)+(x-y)=(x-y)(x^2+xy+y^2+1).x^3-x^2-y^3+y^2=(x^3-y^3)-(x
您好:x的三次方(y-x)的三次方-(x-y)的三次方=x的三次方(y-x)的三次方+(y-x)的三次方=(x³+1)(y-x)³=(x+1)(x²-x+1)(y-x)&
x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy
y的三次方
x1³+x2³=(x1+x2)(x1²-x1*x2+x2²)=(x1+x2)[(x1+x2)²-3x1*x2]=3×(3²-3×1)=3×6
T(r+1)=C(10,r)x^(30-3r)·(1/2)^r·x^(-2r)30-5r=0r=6C(10,6)·(1/2)^6=105/32