y3-25y分解因式
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 04:40:02
这是一个完全平方公式4(x+y)²-20(x+y)+25=[2(x+y)]²-2x5x2(x+y)+5²=[2(x+y)-5]²再问:能帮我讲解一下吗?再答:例
16(x+y)的平方-25(x-y)的平方=[4(x+y)]^2-[5(x-y)]^2=[4(x+y)+5(x-y)][4(x+y)-5(x-y)]=(9x-y)(9y-x)
1-6y+y²=y²-6y+9-8=﹙y-3﹚²-8=﹙y-3-2√2﹚﹙y-3+2√2﹚.
=(x+2y)(x-2y)(x-2y)
∵代数式x3+y3+3x2y+axy2含有因式x-y,∴当x=y时,x3+y3+3x2y+axy2=0,∴令x=y,即x3+x3+3x3+ax3=0,则有5+a=0,解得a=-5.将a=-5代入x3+
1)18m(m-n)的平方-12(n-m)的平方=6(m-n)²2)x的m+3次方y-x的m+2次方y平方+x的m+1次方y3次=x的m+1次方y(x²-xy+y²)再问
=[5(x+y)]²-[4(x-y)]²=(5x+5y+4x-4y)(5x+5y-4x+4y)=(9x+y)(x+9y)
25(x+y-3)²-9(3x-2y)²(5x+5y-15)²-(9x-6y)²(5x+5y-15+9x-6y)(5x+5y-15-9x+6y)(14x-y-1
16(x+y)的平方-25(x-y)的平方=[4(x+y)+5(x-y)][4(x+y)-5(x-y)]=(9x-y)(9y-x)
25(x-2y)³+4(2y-x)=(x-2y)[25(x-2y)²-4]=(x-2y)[5(x-2y)+2)][5(x-2y)-2]=(x-2y)(5x-10y+2)(5x-10
^3代表3次方,^2代表平方X^3+X^2-Y^3-Y^2=(x^3-y^3)+(x^2-y^2)=(x-y)(x^2+xy+y^2)+(x-y)(x+y)=(x-y)(x^2+xy+y^2+x+y)
1.2a(x-y)-3b(y-x)=2a(x-y)+3b(x-y)=(2a+3b)(x-y)2.-x^y-2xy+35y=-y(x^+2x-35)=-y(x-7)(x+5)3.a^(x-y)-4b^(
(x+y)2-10(x+y)+25=(x+y)2-10(x+y)+(-5)2=(x+y-5)2.故答案为:(x+y-5)2.
你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解
错了,中间是+40(x²-y²)原式=[4(x+y)]²+2[4(x+y)][5(x-y)]+[5(x-y)]²=[4(x+y)+5(x-y)]²=(
解题思路:利用立方差公式灵活进行分析。解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/includ
x3次方-xy平方+x平方y-y3次方=x(x²-y²)+y(x²-y²)=(x+y)(x²-y²)=(x+y)(x+y)(x-y)=(x+
x^3+y^3+z^3-3xyz=[(x+y)^3-3x^2y-3xy^2]+z^3-3xyz=[(x+y)^3+z^3]-(3x^2y+3xy^2+3xyz)=(x+y+z)[(x+y)^2-(x+
6xy2-9x2y-y3+y=-y(9x^2-6xy+y^2-1)=-y{(3x-y)^2-1}=-y(3x-y+1)(3x-y-1)