x平方+2x分之x平方-1÷x分之x-1-搜答案-搜搜做题作业网

x+2分之x平方-2x-x-1分之x平方-4X+4除以x平方-16分之x平方+4x=x(x-2)/(x+2)÷(x-2)^2/(x-1)÷[x(x+4)/(x+4)(x-4)]=[x(x-2)/(x+

原式=[(x²+2x)/(x²+4x+4)]÷[(2x²-8)/(3x+6)]÷[1/(x²-4)]=[x(x+2)/(x+2)²]÷{2(x+2)(

x^2+3x+1=0x+1/x=-32x^2+2/x^2=2[(x+1/x)^2]-4=2*9-4=14

（3-x分之x-1）平方÷（x平方-6x+9分之9-x平方）平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]

=-(x-1)/(x+2)(x-1)×(x+2)/(x+1)(x-1)=-1/(x+1)(x-1)=-1/(x²-1)=1/(1-x²)

x平方-x+1=x平方-x分之6-x+1=-x分之6x-x分之6-1=0x平方-x-6=0(x-3)(x+2)=0x-3=0,x+2=0所以,x=3.x=-2

=2x/x²-(2x-1)/x²=(2x-2x+1)/x²=1/x²

=[(x+1)(x-1)/(x-1)²-(x-1)/(x+1)]×(x-1)/x=[(x+1)²-(x-1)²]/(x+1)(x-1)×(x-1)/x=4x/(x+1)(

=[(x+2)/x(x-2)-(x-1)/(x-2)²]×(x-4)/x=[(x-2)(x+2)-x(x-1)]/x(x-2)²×(x-4)/x=(x-4)/x(x-2)²

x平方-6x+8=x²-2×3x+9-9+8=（x-3）²-1=（x-3-1）（x-3+1）=（x-4）（x-2）x平方+x-6=（x-2）（x+3）12+x-x平方=（4-x）（

x的平方-2x+1分之x-3÷x-1分之x的平方-9=[(x-3)/(x-1)²]*[(x-1)/(x+3)*(x-3)]=1/(x-1)(x+3)

0.5（x+1）的平方

=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(4-x)=[(x²-4-x²+4)/x(x-2)²]×x/(4-x)=1/(x-2)²

=x/(x+2)(x-2)-(x-2)/(x+2)(x-2)=[x-(x-2)]/(x+2)(x-2)=2/(x²-4)

①X平方+2X分之X+2-X平方-4X+4分之X-1=(x+2)/x(x+2)-(x-1)/(x-2)²=[(x-2)²-x²+x]/x(x-2)²;=(4-3

4-4x分之9x-9=9(x-1)/4(1-x)=-9/4

7/x(x+1)-6/(x+1)(x-1)=-1/x(x-1)两边乘以x(x+1)(x-1)得7(x-1)-6x=-(x+1)7x-7-6x=-x-12x=6∴x=3经检验：x=3是方程的解

=(x+1)(x-1)/(x+3)²×[-1/(x-1)]×(x+3)/(x²+4)=-(x+1)/(x+3)(x²+4)

原式=[（x+2）/x（x-2）-（x-1）/（x-2）²]÷（4-x）/x=[（x+2）（x-2）/x（x-2）²-x（x-1）/x（x-2）²]÷（4-x）/x=[（

原式=[2x(x+1)/(x+1)(x-1)-x(x-1)/(x-1)²]÷x/(x+1)=[2x/(x-1)-x/(x-1)]×(x+1)/x=x/(x-1)×(x+1)/x=(x+1)/