x⁴ 3x³ 11x² 9x 18

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x⁴ 3x³ 11x² 9x 18
把下面的等式改写成比例.1.6a=7b 2.3×45=15×9 3.3分之2x=0.75Y 4.8X9=4X18

1.6a=7ba:b=7:62.3×45=15×93:15=9:453.3分之2x=0.75Yx:y=0.75:2/34.8X9=4X188:4=18:8

0.78x18÷0.15,0.25x(4+0.4),7.28+3.2÷2.5,3.25x67+5.57x67可以简便算法

ls强人1.原式=78÷15x18=93.62.原式=0.25x4+0.25x0.4=1+0.1=1.13.原式=7+0.28+32/25=7+7/25+32/25=8又14/254.原式=67x(3

|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

因式分解3x*x+11x+10

3x*x+11x+10=(3x+5)(x+2)

x+2/x^2-x-6 + 2x/x^3-3x - x+1/x^2-6x+9

中间错了原式=(x+2)/(x-3)(x+2)+2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)+2/(x-3)-(x+1)/(x-3)²=3/(x-3)-(x+1)/

1 简便计算:40/29x18-11x18/29+92 2 求2x+3y=12的解

1:(40/29-11/29)×18+92=1102:x=0,y=4;x=2,y=3;x=3,y=2;x=6,y=0就这些,负数你们用不到吧

(x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9)

原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-

解方程(x^2+3x)/(2x^2+2X-8)+(x^2+x-4)/(3x^2+9X)=11/12

提示,设t=(x^2+3x)/(x^2+X-4)算出t再求x

求x^2-3x/x^2-6x+9*x^2-11x+30/x^2-5x-1

原式=[x(x-3)/(x-3)²][(x-5)(x-6)/x(x-5)]-1=[x/(x-3)][(x-6)/x]-1=(x-6)/(x-3)-1=(x-6-x+3)/(x-3)=-3/(

计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)

(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-

如果3x*x-x=1那么9x*x*x*x+12x*x*x-3x*x-7x+2001等于多少

应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x

解方程:x+5除以x+3加上x+11除以x+9等于x+7除以x+5加上x+9除以x+7

x+5除以x+3加上x+11除以x+9等于x+7除以x+5加上x+9除以x+7即(x+5)/(x+3)+(x+11)/(x+9)=(x+7)/(x+5)+(x+9)/(x+7),分析后,可知分子=分母

解方程x²+3x-9=x-11

x²+3x-9=x-11x²+3x-x-9+11=0x²+2x+2=0Δ=2²-4*1*2=-4

填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x

136487259875239146942615837693572418584961372217348695468753921359126784721894563

x^9+x^6+x^3-14

设x^3=a,则题目可变为下式:a^3+a^2+a-14=a^3-8+a^2+a-6=(a-2)(a^2+2a+4)+(a-2)(a+3)=(a-2)(a^2+2a+4+a+3)=(a-2)(a^2+

化简:9x-12x+5x,3x-5x-2+5x+8,3x+5+2x+3-7-11x

9x-12x+5x=-3x+5x=2x3x-5x-2+5x+8=-2x+5x-2+8=3x+63x+5+2x+3-7-11x=3x+2x-11x+5+3-7=5x-11x+8-7=-6x+1

ARM9中:MOV R2,#0x18 书上解释说是给R2赋值为40,这是为什么?如果是40,不应该是MOV R2,#0x

不可能.第一条指令书上写错了.应该是#0X28,要用怀疑的眼光去看书.多参考参考.