x² y²=4x-3如何化简

原式=16x²-24xy+9y²-25x²-10xy-y²+9x²-6xy-8y²=-40xy=-40*1/3*6=-80

3x+2=y和11x=y,得到x=1/4,y=11/4,5X+4=Y和7X+6=Y,得到X=-1,Y=-1代入9X+8=y,不成立,方程组无解..

X^2+Y^2-4X+6Y+13=0(x-2)^2+(y+3)^2=0x=2,y=-3(3X+Y)^2-3（3X-Y）(X+Y)-(X-3Y)(X+3Y)=9x^2+6xy+y^2-3(3x^2+2x

原式=x^2+9xy+20y^2-(x^2-25y^2)=9xy+45y^2把x=3,y=-1/3原式=-9+45*1/9=-4

感觉你题目写错了式子应该是这样[(y-2x)(-2x-y)-4(2x-y)^2]÷3y我就按我写的式子做了原式=[(2x-y)(2x+y)-2(2x-y)]÷3y=(2x-y)(2x+y-2)÷3y当

[(y-2x)(-2x-y)-4(x-2y)²]÷3y=[4x^2-y^2-4x^2+16xy-16y^2]/3y=[16xy-17y^2]/3y=16x/3-17y/3再问：a²

原式可化为[(15x²+16xy+4y²)+(x²-4y²)]/4x=(16x²+16xy)/4x=4x+4y代入得4×2+4×3=20

8x^2-20xy+5x^2-16x^2+10xy-3x^2-10xyx=1,y=3-3-30=-33

解题思路：对于这种等式一定可以化成平方相加的形式，这里面要使用到完全平方公式。解题过程：

(7x-2y)(3x-2y-1)-(4x+3y)(9x+6y)=21x^2-14xy-7x-6xy+4y^2+2y-36x^2-24xy-27xy-18y^2=-15x^2-70xy-7x-14y^2

化简求值2(x-zy)^2-4(x-2y)+(x-2y)^2-3(x-2y),其中x=-1,y=1/2.2（x+2y）²-4(x-2y)+(x+2y)²-3(x-2y)=3(x+2

3x+4y=403(1)4x+3y=416(2)（1）式两边同时乘4得：12x+16y=1612(3)（2）式两边同时乘3得：12x+9y=1248(4)(3)式减(4)得：7y=364y=52y=5

原式=4x-2y-（-2x+2y+2x+y）-4x=4x-2y+2x-2y-2x-y-4x=-5y，当x=0，y=-3时，原式=-5×（-3）=15．

原式=[x^2-y^2-x^2+2xy-y^2+2xy-2y^2]/4y=2x-2y=2(x-y)=2*-3/2=-3很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2=5xy^2-3xy^2+(4xy^2-2x^y)+x^2y-xy^2=5xy^2-3xy^2+4xy^2-2x^y+x^2y-

原式=[(5x²+8xy-4y²)-(9x²-4y²)]÷4x=(-4x²+8xy)÷4x=-x+2y当x=2,y=-1时原式=-2-2=-4

[4(x^2+y)(x^2-y)-(2x^2-y)^2]÷y=[4(x^4-y²)-(4x^4-4x²y+y²)]÷y=[4x^4-4y²-4x^4+4x

应用平方差公式a^2-b^2=(a+b)(a-b)(x+y+z)(x+y-z)(x-y+z)(-x+y+z)=[(x+y)^2-z^2][z^2-(x-y)^2]=-z^4+[(x+y)^2+(x-y

3x+y求采纳

原式左边：X^2+X-Y^2-Y=x^2-y^2+x-y=(x-y)(x+y)+(x-y)×1=(x-y)(x+y+1)