搜搜做题作业网x^2 xy-y^2 3x-3y
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 14:13:03
原式=x²-y²-(4x²y²+12xy²+9y²)=x²-y²-4x²y²-12xy²-
3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)
对.前提是x不等于y
3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy
3xy[2xy-x（y-2）+x]＝3xy[2xy-xy+2x+x]=3xy(xy+3x)=3x²y²+9x²y
(3xy)平方/(-xy)+(x-2y)平方-(x+2y)(x-2y)=-9xy+(x-2y)(x-2y-x-2y)=-9xy+(x-2y)(-4y)=-9xy-4xy+8y²=8y
(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^
x^3+x^2y-xy^2-y^3=（x-y）(x^2+xy+y^2)+xy(x-y)=(x-y)(x^2+y^2+2xy)=(x-y)(x+y)^2
x^2-2xy-3y^2+x+y=x*x-2*x*y-3*y*y+x+y=(x-3y)(x+y)+(x+y)=(x+y)(x-3y+1)如果是初中生,分解到这里就可以了如果是高二及以上,可能要在复数范
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【x²+xy/（x-y）】/【xy/（x-y）】=【x²（x-y）/（x-y）+xy/（x-y）】/【xy/（x-y）】={【x²（x-y）+xy】/（x-y）}/【xy
符号好像有问题.x³+x²y-xy²-y³=x²(x+y)-y²(x+y)=(x+y)(x²-y²)=(x-y)(x+y
x^3y+2x^2y^3+xy^3=xy(x^2+2xy+y^2)=xy(x+y)^2再问：公式法——完全平方再答：对，第一步提取公因式
[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/
[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx&sup
1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)
x²y+3xy²-x-3y=xy(x+3y)-(x+3y)=(x+3y)(xy-1)
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
原式=xy(x-y)+(x-y)(x^2+xy+y^2)=(x-y)(x^2+2xy+y^2)=(x-y)(x+y)^2
-x³y³-x²y²-xy=-xy(x²y²+xy+1)