xy-[2x 5x-1]-[xy-2 3x 1]

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xy-[2x 5x-1]-[xy-2 3x 1]
用分组分解法因式分解1、4x的平方-4xy-a的平方+y的平方x的平方-2y-4y的平方+x5x的平方-10xy+5y的

4x^2-4xy-a^2+y^2=(2x-y)^2-a^2=(2x-y-a)(2x-y+a)x^2-2y-4y^2+x=(x+1/2)^2-(2y+1)^2=(x-2y-1/2)(x+2y+3/2)5

xy(xy+1)+(xy+3)-2(x+y+2分之一)-(x+y-1)的平方

xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2=xy(xy+1)+(xy+1)+2-2(x+y)-1-[(x+y)^2-2(x+y)+1]=(xy+1)^2+2-2(x+y)

1/2≥(2/xy)^2 求xy大小?

1/2≥(2/xy)^2==》√2/2≥|2/xy|==》√2≤|xy/2|==》2√2≤|xy|==》xy≤-2√2或2√2≤xy

先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1

1.2(Xy+Xy)-3(Xy-xy)-4Xy=2*2xy-0-4xy=4xy-4xy=02.1/2ab-5aC-(3acb)+(3aC-4aC)=1/2ab-5ac-3acb-ac=1/2ab-6a

(x+y-2xy)(x+y-2)+(1-xy)²

(x+y-2xy)(x+y-2)+(1-xy)^2=(x+y)^2-2(1+xy)(x+y)+4xy+1-2xy+x^2y^2=(x+y)^2-2(1+xy)(x+y)+(1+xy)^2=(x+y)^

计算3xy[2xy-x(y-2)+x-1]

3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy

1、xy²+2xy-x(因式分解)

xy²+2xy-x=x(y²+2y-1)=x(y²+2y+1-2)=x[(y+1)²-2]=x(y+1+√2)(y+1-√2)再问:太厉害啊,那再做多两题吧,也

5x^2y/-1/2xy*3xy^2

5x^2y/-1/2xy*3xy^2=-7.5x²y²

已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值

解(x+1)平方+/y-1/=0∴x+1=0,y-1=0∴x=-1,y=1∴2(xy-5xy平方)-(3xy平方-xy)=(2xy+xy)+(-10xy平方-3xy平方)=3xy-13xy平方=3×(

当x=3,y=3分之1时,求代数出3xy-[2xy-2(xy-2分之3xy)+xy]+3xy的值

3xy-[2xy-2(xy-2分之3xy)+xy]+3xy=6xy-[2xy-2xy+3xy+xy)=6xy-4xy=2xy=2×3×3分之1=2

若(1)xy>0,(2)xy<0,求|x|/x+|y|+|xy|/xy的值

这个是原题要求的吧|x|/x+|y|/y+|xy|/xy(1)xy>0x,y都大于零或都小于零x,y都大于零时|x|/x+|y|/y+|xy|/xy=|x|/x+|y|/y+|xy|/xy=x/x+y

已知:xy+x=-1,xy-y=-2.

(1)∵xy+x=-1①,xy-y=-2②,∴①-②得x+y=1;(2)先把xy+x=-1,xy-y=-2的值代入代数式,得原式=-x-[2y-1+3x]+2[x+4]=-x-2y+1-3x+2x+8

因式分解xy²-2xy+x+2y-1

因式分解xy²-2xy+x+2y-1解xy²-2xy-y²+x+2y-1=xy²-2xy+x-y²+2y-1=x(y²-2y+1)-(y&#

1-(3xy-x)+【-2(2x+3xy)】

原式=1-3xy+x+(-4x-6xy)=1-3xy+x-4x-6xy=1-3x-9xy

3xy-3xy-xy+2yx

3xy-3xy-xy+2yx=-xy+2xy=xy

【(2+xy)(xy-2)-xy(xy+1)+4】/(-2xy) 一道计算题!

=(x²y²-4-x²y²-xy+4)/(-2xy)=-xy/(-2xy)=1/2

y^3+xy^2+2xy+x^2-1 因式分解

y^3+xy^2+2xy+x^2-1=(x+y-1)(x+y^2+y+1)再问:烦写出过程再答: 

因式分解:-1/3(xy+3)^2+3(3-xy)^2

-1/3(xy+3)^2+3(3-xy)^2=(-1/3)[(xy+3)²-9(3-xy)²]=(-1/3)(xy+3+3(3-xy))(xy+3-3(3-xy))=(-1/3)(

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy),其中x=20,y=-25分之1

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+

化简!1、(x^2-xy)+xy+y^2 2、3(x^2-xy)-xy+y^2

再答:望采纳,谢谢!可以继续追问哟^_^再问:过程再答:好的,马上哈再答:再答:就是合并同类项的意思再答:再答:好的,谢谢哈^_^