x=1*2 2*3 3*4... 99*100 matlab

6x+3/2x=97.5x=9x=9÷7.5x=1.22x-4/3x=1/22/3x=1/2x=1/2*3/2x=3/4x+9/2=12x=12-9/2x=7.5x-0.8x=220.2x=22x=2

原式右=22x^2-33x+1=22x^2-33x+11-10=11(2x^2-3x+1)-10令：y=2x^2-3x+1则原式简化为：y^2=11y-10计算得到：y=10ory=1当y=10时,x

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

1）（x-3）/（x-2）-（x-5）/（x-4）=（x-7）/（x-6）-（x-9）/（x-8）化简得【（x-3）（x-4）-（x-5）/（x-2）】/【（x-2）（x-4)】=【（x-7）（x-8

 再问：额、不懂再答： 再答：后面的看做一个整体再问：好的吧、谢谢大神再答：回来的话，请采纳再问：啊、突然明白了呢。。。

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

3×x=1/10x=1/10×1/3=1/30x×9=12/13x=12/13×1/9=4/3921×x=70/33x=70/33×1/21=70/69322x=33/45x=33/45×1/22=1

令(3X+1)=t,X=1/3(t-1)F(t)=9×［1/3(t-1)]²-6×［1/3(t-1)］+4=t²-2t+1-2t+2+4=t²-4t+7∴f(x)=x&#

(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/

4x+7=9x+229x-4x=7-225x=-15x=-32(x-2)-3(4x-1)=9(1-x)2x-4-12x+3=9-9x2x-12x+9x=9+4-3-x=10x=-10

/>(4X+2)/X+【4(X-5)-2】/(X-5)=【(X-4)-2】/(X-4)+【7(X+1)+2】/(X+1)4+2/X+4-2/(X-5)=1-2/(X-4)+7+2/(X+1)8+2/X

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

(x+2)/(x+3)-(x+1)/(x+2)=(x+8)/(x+9)-(x+7)/(x+8)(x+2)²/[(x+2)(x+3)]-(x+1)(x+3)/[(x+2)(x+3)]=(x+8

同分化简得32x+128/(x+1)(x+3)(x+5)(x+7)=0所以得x=-4给分吧算了好久的····

应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x

1.9/x+x=6,x^2+9=6x,x^2-6x+9=0,(x-3)^2=0,x=3.2.(x+1)/x+2x/(x+1)=3两边同乘以x（x+1)2x^2+(x+1)^2=3*x*(x+1)2x^

第一个：3x/4=1/2,x=(1/2)*3/4=2/3第二个：没有=后面的数字第三个:0.2x=22,x=110第四个：7/10x=98,x=140

X=-1把等式左边全部移到右边,得(2x+2)/2+(2x+2)/3+.+(2x+2)/9=0再提取公因2(x+1)(1/2+1/3+.+1/9)=0x+1=0所以x=-1

2x/x^2-9=x-1/x^2-6x+9-1/x+32x/(x+3)(x-3)=(x-1)/(x-3)²-1/(x+3)两边同乘以(x-3)²(x+3)2x(x-3)=(x-1)

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/