输出100-1000之间能被37整除的数.
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#includevoidmain(){inti;for(i=1;i
111,148,185,222,259,296,333,370,407,444,481,518,555,592,629,666,703,740,777,814,851,888,925,962,999.
PrivateSubCommand1_Click()Fori=1000To2000IfiMod17=0ThenPrintiNextiEndSubPrivateFunctionMax(ArrAsVari
我简单写了一个应该符合你的要求:publicclasstests{publicstaticvoidmain(String[]args){intn=0;for(inti=0;i
程序如下:main(){inti;for(i=1;i
#includevoidmain(){inti;for(i=102;i
//C#代码privatevoidForm1_Load(objectsender,EventArgse){//取出符合条件的数Listnums=newList();for(inti=100;i
C语言版本如下:#includeintmain(){inti,sum=0;for(i=1;i
/>vararr=[];//存放结果varnum=1;//初始变量while(num再问:用while循环嘛!我看不懂,表示有鸭梨再答:这就是while循环啊
inta3=0,a7=0,a37=0;for(inti=1;i
PrivateSubForm_Click()Dimx1%,x2%,count%count=0Fori=1To100x1=iMod5x2=iMod7Ifx1=0Andx2=0ThenPrinti;End
for(inti=100;i
publicstaticvoidmain(String[]args){for(inti=0;i
#includevoidmain(){inti;for(i=1;i
#includevoidmain(){inti,n=0;for(i=100;i
在excel中A1到A200输入100-300B1=if(mod(A1,21)=0,A1,0)然后下拉B1至B200则能被3和7同时整除的数在Bn中输出,不能的输出0在求和就行了找出的数有105126
Fori=100To999IfiMod10=3AndiMod7=0ThenPrintiEndIfNexti
最简单的做法:#includevoidmain(){inti;for(i=1000;i
intsum=0;for(inti=1;i
Private Sub Command1_Click() Dim j As Long, x&n