调用函数输出一个整数的全部素因子

#include<stdio.h>int getmax(int a,int b){      re

你所需要的程序如下：#includeintcountdigit(intnumber,intdigit);voidmain(){intnum,n=0;printf("请输入一个整数:");scanf("

functioncountdigit(number,digit){vartmp=(number+"").replace(/[^2]/ig,"");returntmp.length;}

#include#include#include#includeusingnamespacestd;//计算num内的所有素数（不包括num）voidCalcPrimes(intnum,vector&

#includemain(){inta,b;printf("输入整数a,b:");scanf("%d,%d",&a,&b);c=func(a,b);printf("a*a+b*b=%d\n",c);}

楼主你好,这是源程序,是用辗转相除法写的#includeintmax(intp_a,intp_b){\x09if(p_b==0)\x09\x09returnp_a;\x09else\x09\x09re

include"stdio.h"intcountdigit(inta,intb){\x09intcount=0;\x09do\x09{\x09\x09if(b==a%10)\x09\x09\x09co

#includeintprime(intn){if(n

}while(number==0);==>}while(number!=0);

具体代码如下：#includeintcountdigit(intnumber,intdigit){intcount=0;while(number){if((number%10)==digit)coun

#include <stdio.h>#include <math.h>int main(void){  long i

#includevoidfun(intm,intn){\x05printf("%d\n",m*m+n*n);}main(){\x05intm,n;\x05while(scanf("%d%d",&m,&

#include#includeintfun(intn){intsum=0,i;for(i=1;i

我用C语言编一下啊.其他语言类似!#includevoidsort(intn){if(n%2==0)printf("thenumberisdouble\n");elseprintf("thenumbe

#includeintgcd(intm,intn){\x09intr;\x09do\x09{\x09\x09r=m%n;\x09\x09m=n;\x09\x09n=r;\x09}while(r!=0)

首先你那个a[i]=a[i]*(n-j)/j公式有点问题吧,这样会输出全是1的啊...如果还是按照你这样可以改成如下代码：#include"stdafx.h"#include#include#incl

#include"stdio.h"intfunc(inta,intb){inttemp;while(b!=0)/*利用辗除法,直到b为0为止*/{temp=a%b;a=b;b=temp;}retu

#include/*C语言*/intmaxNum(inta,intb){return(a>b?a:b);}voidmain(){inta,b,max;printf("Entertwonumbers!\

判断条件错了if(x%i!=0)换成if(x%i==0)

#includeusingnamespacestd;boolpanduan(intn){intm=n%2;if(m==0)returntrue;elsereturnfalse;}intmain(){i